e=1....in mathematics

[shek]

theorem : e=1
Proof:

let 2*e = f-------------->(1)
where f>0
rasing to the power 2*pi*i

(1)==>2^(2*pi*i) * e^(2*pi*i) = f^(2*pi*i)-------------->(2)

but,e^(2*pi*i) = 1 (since from complex no.s , i.e. e(2*pi*i) =cos(2*pi)+i sin(2*pi) )

Therefore
(2)==>2^(2*pi*i) = f^(2*pi*i)
==>2=f (since power are equal bases can be equated)
Thus, from (1), we have....
e=1


any contradictions to this????????
waiting for ur replies....

here..
for example...
3^2 = 9
2^4 = 16

[phillia]

Interesting..

But wrong section.
/moved.

[azzi371]

Im not that good at math...interesting though...

[shek]

friends I want contradictions....
I'll be comin with another iin one or 2 days

[princearthas]

isn't that a proven theorem
i did remember doing that in math course couple of years back

[shek]

buddy....
see the theorem clearly....I have proved it
& it is wrong some where ...that u should find out

[shek]

no contradictions till now &

[shek]

no body has any objections?????
okay.... can this be closed then ???